ValueError: could not convert string to float: . - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: ValueError: could not convert string to float: . (/thread-7296.html) |
ValueError: could not convert string to float: . - BoaCoder3 - Jan-03-2018 In this programme i'm trying to solve a mathematical ratio problem, then calculate the squareroot, however, whenever i try to give it input like this: 2.5, it throws out the following error: , obviously it doesn't recognise the "." as a number. Here's the complete code:# !/usr/bin/python # -*- coding: utf8 -*- import math def data_processing(): ratio = list(raw_input('ratio numbers: ').replace(' ', '')) r1 = float(ratio[0]) * float(ratio[1]) r2 = float(ratio[2]) * float(ratio[3]) a = r1/r2 print math.sqrt(a) data_processing()How can i get the float() function to recognise a number like this: 2.5 as a floating point number with a decimal point instead of a group of numbers with the string "."? what is the easiest way to fix this? thanks RE: ValueError: could not convert string to float: . - Windspar - Jan-03-2018 Python does recognize '.' as float. You need to print ratio. To see your error. RE: ValueError: could not convert string to float: . - buran - Jan-03-2018 what is expect user input at this line ratio = list(raw_input('ratio numbers: ').replace(' ', '')) >>> var1 = '2.5' >>> var2 = float(var1) >>> var2 2.5 >>> type(var2) <type 'float'> >>> RE: ValueError: could not convert string to float: . - atlass218 - Aug-24-2019 perhaps you want to write this sample code like that : ratio = list(raw_input('ratio numbers: ').replace(' ', '.')) |