Sequence subtraction - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: Game Development (https://python-forum.io/forum-11.html) +--- Thread: Sequence subtraction (/thread-9396.html) |
Sequence subtraction - Tbot - Apr-06-2018 Hello! I am making a game where you enter a path for a drone to fly in, and you must enter the movements right. In the case below, the correct way to get through would be the sequence sddddwx. However, the player can get a 'free-bee', and have any number of characters wrong, and still pass. The errors that will pass unnoticed will be defined using the variable error. How would I make a program that would not notice a number of wrong characters? Thank you. The error is defined: print"Newest upgrade purchased!" error = error + 1 money = money - 1000000 print"You can make",error," mistakes."The maze: print(""" |A----B| From A drop Paratrooper 4 (v) at B |______| Time limit: None.""") r1 = raw_input("Commands:") RE: Sequence subtraction - Windspar - Apr-06-2018 1. Next time. Show the work. That you want help on. It pretty simple. Just loop over word. Compare against correct word code. Try it yourself then look at code. RE: Sequence subtraction - Tbot - Apr-06-2018 What do you mean by Quote:Just loop over word. RE: Sequence subtraction - Windspar - Apr-06-2018 Loop over the word. Then you compare it to your correct output. for loop. word = 'sdddwx' for letter in word: print(letter)for range loop word = 'sdddwx' for i in range(len(word)): print(word[i])while loop word = 'sdddwx' length = len(word) i = 0 while i < length: print(word[i]) i += 1 RE: Sequence subtraction - Tbot - Apr-06-2018 How do I compare it against the correct word code? RE: Sequence subtraction - Windspar - Apr-06-2018 1. Seems like you need to go through the beginner tutorials. Before making a game. basic programming. a. variables (integer, float, strings, etc) b. logic and logic operators (if .. elif .. else) (==, !=. etc) c. loops (for, while) d. functions (def) e. containers (tuple, list, dict, class) f. keywords If logic. code = 'sddddwx' word = 'sdddwwx' if word[0] == code[0]: print(True)example. Try mixing logic with a loop. Before looking at code. RE: Sequence subtraction - Tbot - Apr-07-2018 Now, how do I get rid of errors if the string is only one letter, while using the code below: code = raw_input("Code:") errors = 0 word = 'sdddwwx' if word[0] == code[0]: print("Good!") else: errors = errors + 1 if word[1] == code[1]: print("Good!") else: errors = errors + 1 RE: Sequence subtraction - ljmetzger - Apr-07-2018 Take a look at the Hide/Show in Windspar's last post. RE: Sequence subtraction - Windspar - Apr-07-2018 To solve your problem. A few keywords and a loop with logic. keyword min print(min(5, 3))keyword range. print(list(range(10)) for i in range(10): print(i)keyword len word = 'sddwx' print(len(word))play with code. try to solve it yourself. then look at code in above post. RE: Sequence subtraction - Tbot - Apr-08-2018 So, this is the final code: errorlevel = 0 errors = 0 r1 = raw_input("Commands:") word = 'sdddwwx' for i in range(min(len(r1), len(word))): if r1[i] != word[i]: errors += 1 if errorlevel >= errors or errors == 0: print"Good!" else: print errorsThank you for your help. |