changing tkinter label from thread

[Yoriz]

The thread should not be called with the method run, it should be called with the method start.
Inside the thread you have created a new instance of MainPage, the thread will need passing a reference to MainPage.
When calling the GUI from a thread you need to use the method after or the GUI will lockup.

I removed the use of keyboard as I don't have it installed.

import tkinter as tk
import time
from threading import Thread


class MainPage(tk.Frame):
    def __init__(self, *args, **kwargs):
        super().__init__(**kwargs)
        self.state_lbl = tk.Label(self, text="initial words")
        self.state_lbl.grid(row=0, column=0)

    def changeState(self, text):
        self.state_lbl['text'] = text


class MyFunctions:

    def __init__(self, gui):
        self.gui = gui

    def one(self):
        time.sleep(5)
        print("one")
        self.gui.after(0, self.gui.changeState("updated words"))
        time.sleep(1)

    def two(self):
        print("two")
        time.sleep(1)
        self.gui.after(0, self.gui.changeState("updated words again"))


class runCycle(Thread):
    def __init__(self, gui):
        Thread.__init__(self)
        my = MyFunctions(gui)
        self.twoFunctions = [my.one, my.two]

    def run(self):
        for func in self.twoFunctions:
            func()


if __name__ == "__main__":
    root = tk.Tk()
    main = MainPage(root)
    main.grid()
    root.wm_geometry("600x300")
    run_instance = runCycle(main)
    run_instance.start()
    root.mainloop()

Take a look at the following [Tkinter] How to deal with code that blocks the mainloop, freezing the gui