itertools

[jarrod0987]

I know how to use itertools for permutations in the normal way.

permutations = (['a', 'b', 'c'], 2)

would give
[a, b]
[a, c]
[b, a] etc...

What if I want each element in the permutation to have a separate list?
something like:

permutations = (['a', 'b'], ['c', 'd', 'e'] 2)

which would give
[a, c]
[a, d]
[a, e]
[b, c]
[b, d]
[b, e]

Thanks

[buran]

What you describe is not permutation...

from itertools import product
print(list(product(['a', 'b'], ['c', 'd', 'e'])))

Output:
[('a', 'c'), ('a', 'd'), ('a', 'e'), ('b', 'c'), ('b', 'd'), ('b', 'e')]